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37 michaesp 1
      program calcnewdate
2
C     ===================
3
 
4
      implicit none
5
 
6
      integer   date1(5),date2(5)
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      integer	iargc
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      real      diff
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      character*(80) arg,yychar,cdat
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      character*(2)  cdate(5)
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      integer	flag,nc
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c     check for sufficient requested arguments
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      if (iargc().ne.2) then
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        print*,'USAGE: newtime date (format (YY)YYMMDD_HH(MM)) timestep'
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        call exit(1)
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      endif
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19
c     read and transform input
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      call getarg(1,arg)
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      call lenchar(arg,nc)
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      if (nc.eq.9) then
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        yychar=''
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        read(arg(1:2),'(i2)',err=120)date1(1)
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        read(arg(3:4),'(i2)',err=120)date1(2)
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        read(arg(5:6),'(i2)',err=120)date1(3)
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        read(arg(8:9),'(i2)',err=120)date1(4)
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        date1(5)=99
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      else if (nc.eq.11) then
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        yychar=arg(1:2)
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        read(arg(3:4),'(i2)',err=120)date1(1)
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        read(arg(5:6),'(i2)',err=120)date1(2)
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        read(arg(7:8),'(i2)',err=120)date1(3)
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        read(arg(10:11),'(i2)',err=120)date1(4)
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        date1(5)=99
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      else if (nc.eq.13) then
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        yychar=arg(1:2)
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        read(arg(3:4),'(i2)',err=120)date1(1)
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        read(arg(5:6),'(i2)',err=120)date1(2)
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        read(arg(7:8),'(i2)',err=120)date1(3)
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        read(arg(10:11),'(i2)',err=120)date1(4)
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        read(arg(12:13),'(i2)',err=120)date1(5)
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      else
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        print*,'USAGE: newtime date (format (YY)YYMMDD_HH(MM)) timestep'
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        call exit(1)
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      endif
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48
      call getarg(2,arg)
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      call checkchar(arg,".",flag)
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      if (flag.eq.0) arg=trim(arg)//"."
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      read(arg,*) diff
52
 
53
      call newdate_test(date1,diff,date2)
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55
      if ((date2(1).lt.date1(1)).and.
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     >    (diff.gt.0.).and.
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     >    (yychar.eq.'19')) yychar='20'
58
 
59
      if (date2(1).lt.0) date2(1)=date2(1)+100
60
 
61
      if ((date2(1).gt.date1(1)).and.
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     >    (diff.lt.0.).and.
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     >    (yychar.eq.'20')) yychar='19'
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65
      if (date2(1).lt.10) then
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        write(cdate(1),'(a,i1)')'0',date2(1)
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      else
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        write(cdate(1),'(i2)')date2(1)
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      endif
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      if (date2(2).lt.10) then
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        write(cdate(2),'(a,i1)')'0',date2(2)
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      else
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        write(cdate(2),'(i2)')date2(2)
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      endif
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      if (date2(3).lt.10) then
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        write(cdate(3),'(a,i1)')'0',date2(3)
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      else
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        write(cdate(3),'(i2)')date2(3)
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      endif
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      if (date2(4).lt.10) then
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        write(cdate(4),'(a,i1)')'0',date2(4)
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      else
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        write(cdate(4),'(i2)')date2(4)
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      endif
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      if (date1(5).eq.99) then
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        cdate(5)=''
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      else
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        if (date2(5).lt.10) then
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          write(cdate(5),'(a,i1)')'0',date2(5)
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        else
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          write(cdate(5),'(i2)')date2(5)
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        endif
93
      endif
94
 
95
      cdat=trim(yychar)//cdate(1)//cdate(2)//cdate(3)//
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     >     '_'//cdate(4)//cdate(5)
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      write(*,'(a)')trim(cdat)
98
 
99
      goto 200
100
 
101
 120  write(*,*)
102
     > "*** error: date must be in format (YY)YYMMDD_HH(MM) ***"
103
 
104
 200  continue
105
 
106
      end
107
 
108
      subroutine checkchar(string,char,flag)
109
C     ======================================
110
 
111
      character*(*)	string
112
      character*(1)	char
113
      integer	n,flag
114
 
115
      flag=0
116
      do n=1,len(string)
117
        if (string(n:n).eq.char) then
118
          flag=n
119
          return
120
        endif
121
      enddo
122
      end
123
 
124
      subroutine lenchar(string,lstr)
125
C     ===============================
126
 
127
      character*(*)     string
128
      integer   n,lstr
129
 
130
      do n=1,len(string)
131
        if (string(n:n).eq."") then
132
          lstr=n-1
133
          goto 100
134
        endif
135
      enddo
136
 100  continue
137
      end
138
 
139
      subroutine newdate_test(date1,diff,date2)
140
C     ====================================
141
C
142
C     Routine calculates the new date when diff (in hours) is added to
143
C     date1.
144
C     date1	int	input	array contains a date in the form
145
C				year,month,day,hour,minute
146
C     diff	real	input	timestep to go from date1; if date1(5)
147
C                               is equal to 99, diff is assumed to be
148
C                               given in hours, otherwise in minutes
149
C     date2	int	output	array contains new date in the same form
150
 
151
      integer   date1(5),date2(5)
152
      integer   idays(12)       ! array containing the days of the monthes
153
      real	diff
154
      logical	yearchange
155
 
156
      data idays/31,28,31,30,31,30,31,31,30,31,30,31/
157
 
158
      yearchange=.false.
159
 
160
      if ((mod(date1(1),4).eq.0).and.(date1(2).le.2)) idays(2)=29
161
 
162
      date2(1)=date1(1)
163
      date2(2)=date1(2)
164
      date2(3)=date1(3)
165
      if (date1(5).eq.99) then
166
        date2(4)=date1(4)+int(diff)
167
        date2(5)=0
168
      else
169
        date2(4)=date1(4)
170
        date2(5)=date1(5)+int(diff)
171
      endif
172
 
173
      if (date2(5).ge.60) then
174
        date2(4)=date2(4)+int(date2(5)/60)
175
        date2(5)=date2(5)-int(date2(5)/60)*60
176
      endif
177
      if (date2(5).lt.0) then
178
        if (mod(date2(5),60).eq.0) then
179
          date2(4)=date2(4)-int(abs(date2(5))/60)
180
          date2(5)=date2(5)+int(abs(date2(5))/60)*60
181
        else
182
          date2(4)=date2(4)-(1+int(abs(date2(5))/60))
183
          date2(5)=date2(5)+(1+int(abs(date2(5))/60))*60
184
        endif
185
      endif
186
 
187
      if (date2(4).ge.24) then
188
        date2(3)=date2(3)+int(date2(4)/24)
189
        date2(4)=date2(4)-int(date2(4)/24)*24
190
      endif
191
      if (date2(4).lt.0) then
192
        if (mod(date2(4),24).eq.0) then
193
          date2(3)=date2(3)-int(abs(date2(4))/24)
194
          date2(4)=date2(4)+int(abs(date2(4))/24)*24
195
        else
196
          date2(3)=date2(3)-(1+int(abs(date2(4))/24))
197
          date2(4)=date2(4)+(1+int(abs(date2(4))/24))*24
198
        endif
199
      endif
200
 
201
  100 if (date2(3).gt.idays(date2(2))) then
202
        if ((date2(2).eq.2).and.(mod(date2(1),4).eq.0)) idays(2)=29
203
        date2(3)=date2(3)-idays(date2(2))
204
        if (idays(2).eq.29) idays(2)=28
205
        date2(2)=date2(2)+1
206
        if (date2(2).gt.12) then
207
*         date2(1)=date2(1)+int(date2(2)/12)
208
*         date2(2)=date2(2)-int(date2(2)/12)*12
209
          date2(1)=date2(1)+1
210
          date2(2)=date2(2)-12
211
        endif
212
        if (date2(2).lt.1) then
213
          date2(1)=date2(1)-(1+int(abs(date2(2)/12)))
214
          date2(2)=date2(2)+(1+int(abs(date2(2)/12)))*12
215
        endif
216
        goto 100
217
      endif     
218
  200 if (date2(3).lt.1) then
219
        date2(2)=date2(2)-1
220
        if (date2(2).gt.12) then
221
          date2(1)=date2(1)+int(date2(2)/12)
222
          date2(2)=date2(2)-int(date2(2)/12)*12
223
        endif
224
        if (date2(2).lt.1) then
225
          date2(1)=date2(1)-(1+int(abs(date2(2)/12)))
226
          date2(2)=date2(2)+(1+int(abs(date2(2)/12)))*12
227
        endif
228
        if ((date2(2).eq.2).and.(mod(date2(1),4).eq.0)) idays(2)=29
229
        date2(3)=date2(3)+idays(date2(2))
230
        if (idays(2).eq.29) idays(2)=28
231
        goto 200
232
      endif
233
 
234
      if (date2(2).gt.12) then
235
        date2(1)=date2(1)+int(date2(2)/12)
236
        date2(2)=date2(2)-int(date2(2)/12)*12
237
      endif
238
      if (date2(2).lt.1) then
239
        date2(1)=date2(1)-(1+int(abs(date2(2)/12)))
240
        date2(2)=date2(2)+(1+int(abs(date2(2)/12)))*12
241
      endif
242
 
243
      if (date2(1).lt.1000) then
244
      if (date2(1).ge.100) date2(1)=date2(1)-100
245
      endif
246
 
247
      return
248
      end